বর্ণমালা সিঁড়ি


30

চ্যালেঞ্জ

আপনার টাস্কটি এমন একটি প্রোগ্রাম বা ফাংশন তৈরি করা যা কোনও ইনপুট ছাড়াই নিম্নলিখিতগুলিকে ছাড়িয়ে যায়:

a
bb
ccc
dddd
eeeee
ffffff
ggggggg
hhhhhhhh
iiiiiiiii
jjjjjjjjjj
kkkkkkkkkkk
llllllllllll
mmmmmmmmmmmmm
nnnnnnnnnnnnnn
ooooooooooooooo
pppppppppppppppp
qqqqqqqqqqqqqqqqq
rrrrrrrrrrrrrrrrrr
sssssssssssssssssss
tttttttttttttttttttt
uuuuuuuuuuuuuuuuuuuuu
vvvvvvvvvvvvvvvvvvvvvv
wwwwwwwwwwwwwwwwwwwwwww
xxxxxxxxxxxxxxxxxxxxxxxx
yyyyyyyyyyyyyyyyyyyyyyyyy
zzzzzzzzzzzzzzzzzzzzzzzzzz

স্কোরিং

এটি , তাই প্রতিটি ভাষার সংক্ষিপ্ত উত্তর জিততে পারে।


4
লাইন তালিকা হিসাবে আউটপুট?
— সম্পূর্ণরূপে

5
পরিবর্তে আমরা কি বড় হাতের বর্ণমালা ব্যবহার করতে পারি?
— ঊরীয়েল

9
আমি বর্ণমালার চ্যালেঞ্জ মিস করছি! (তবে লিকি নুনকে জানাবে না)
— লুইস মেন্ডো

9
I worked very hard checking if it was a dupe and apparently it isn't
— Blue

4
@totallyhuman that's up to you.
— SpookyGengar

উত্তর:


14

05AB1E, 2 bytes

Aƶ

Try it online!

Note that this outputs as a list of lines, as the OP explicitly allowed. The link uses a version with pretty-print (joined by newlines).

How it works

  • A yields the lowercase alphabet.
  • ƶ lifts the alphabet (multiplies each element by its index).
  • » joins by newlines.


9

APL (Dyalog), 12 8 5 bytes SBCS

3 bytes saved thanks to @ngn

4 bytes saved thanks to @Adám

⍴⍨⌸⎕A

OP clarified uppercase letters are valid, as well as output as an array of strings.

Try it online!

How?

⌸ gives us every letter in the ⎕A lphabet with its indexes in it, handed into the function ⍴⍨ with the letter as left argument and the indexes as right argument.

⍴⍨ resha ⍴ es its right argument to the length supplied by its left one. ⍨ switches the left and right (therefore the symbol of it, looking like the face of someone reading this explanation).


819⌶↑⎕A⍴¨⍨⍳26
— Adám

@Adám thanks! I tried all variations of / and \, completely ignored shape ⍨
— Uriel

You can remove the ↑ too.
— Adám

@Adám but it would look uglier ⍨
— Uriel

Turn boxing on!
— Adám

8

Haskell, 27 bytes

[c<$['a'..c]|c<-['a'..'z']]

Try it online! Returns a list of lines. (Thanks to @totallyhuman for pointing out that this is now allowed)

Explanation:

             c<-['a'..'z']  -- for each character c from 'a' to 'z'
[           |c<-['a'..'z']] -- build the list of
[   ['a'..c]|c<-['a'..'z']] -- the lists from 'a' to c, e.g. "abcd" for c='d'
[c<$['a'..c]|c<-['a'..'z']] -- with each element replaced by c itself, e.g. "dddd"

*bows* Explanation for a noob? Does <$ repeat its first argument n times, where n is the length of its second argument?
— totallyhuman

@totallyhuman There you go. Feel free to ask in Of Monads and Men if you have further questions.
— Laikoni

There are some very interesting operators in Prelude... Thanks for the explanation!
— totallyhuman

7

brainfuck, 74 bytes

++++++++[>+>+++>++++++++++++<<<-]>++>++>+>+<<[->>[->+<<.>]>[-<+>]<+<+<<.>]

Try it online!

Explanation

++++++++[>+>+++>++++++++++++<<<-]>++>++>+>+
TAPE:
  000
  010   C_NEWLINE
  026   V_ITERCOUNT
  097   V_ALPHA
 >001<  V_PRINTCOUNT
  000   T_PRINTCOUNT

V_ITERCOUNT TIMES:      <<[-   

  V_PRINTCOUNT TIMES:     >>[-
    INC T_PRINTCOUNT        >+
    OUTPUT V_ALPHA          <<.
                          >]

  RESTORE V_PRINTCOUNT    >[-<+>]
  INC V_PRINTCOUNT        <+
  INC V_ALPHA             <+
  OUTPUT C_NEWLINE        <<.
                        >]

Try it online!


7

Befunge-98 (FBBI), 27 bytes

1+:0\::'`j'@+\k:$$>:#,_$a,

where is a substitution character (ASCII 26)

Try it online!

Uses uppercase letters, and has a trailing newline.

Explanation

The code works by storing a counter (0 initially), and on every loop:

  • 1+ - Increments it by 1
  • :0\:: - Pushes things so that the stack looks like this: bottom [N, 0, N, N, N] top
  • '`j'@ - Checks if the counter is greater than 26
    • j'@ - If it is, we jump over the ' and exit using @
    • j'@ - If it isn't, we execute the ', which pushes the ASCII value of @ to the stack

Now the stack looks like this: bottom [N, 0, N, N, 64] top

  • +\ - Adds, then switches the top 2: bottom [N, 0, (N+64), N] top The first time through, this is ASCII 65, or A
  • k: - Duplicates the second from the top (N+1) times - now there are (N+2) values of (N+64) on the stack (plus the N and 0 from earlier)
  • $$ - Throw away the top 2 values - now there are only N values of (N+64)
  • >:#,_ - Prints each top value until it gets to a 0 - this means N copies of (N+64) get printed
  • $ - Throws away the 0 - Now the stack is just N
  • a, - Prints an enter

And it repeats


I like how I used the @ both for ending the program and for adding to the counter.


@JamesHolderness Yep. Thanks for catching that!
— MildlyMilquetoast

7

Ruby, 32 30 bytes

-2 bytes thanks to @EricDuminil.

27.times{|n|puts (n+96).chr*n}

Try it online!


1
Excellent. According to a comment by OP, trailing/leading newlines are allowed. In that case 27.times{|n|puts (n+96).chr*n} would be correct with 30 bytes
— Eric Duminil

6

JavaScript (ES6), 54 bytes

f=(n=9)=>++n<36?n.toString(36).repeat(n-9)+`
`+f(n):''

O.innerText = f()
<pre id=O></pre>


6

Excel VBA, 38 bytes

Using Immediate Window. :)

[A1:A26]="=REPT(CHAR(96+ROW()),ROW())"

Ah. My bad. I thought it's Excel because I used Excel Functions using Immediate Window.
— remoel

You can drop a byte by removing the terminal "
— Taylor Scott


5

Ruby, 38 bytes

Returns an Array of strings

->{(a=*?a..?z).map{|x|x*-~a.index(x)}}

-5 bytes thanks to totallyhuman

*-11 bytes thanks to some excellent golfing by Jordan.


This is only 48 bytes by my count.
— Jordan

1
You don’t need "\n" at all; puts does that for you (though for future reference $/ is 2 bytes shorter)—but you can get rid of puts entirely if you make this a lambda that just returns an array of lines. You can also change a=[*?a..?z];puts a.map to puts (a=*?a..?z).map and x*(a.index(x)+1) to x*-~a.index(x). All together that’s 38 bytes.
— Jordan

The 38-byte version works fine on TiO (see link in previous comment). Note that the (a=*?a..?z) is inside the block, not the arguments part of the lambda.
— Jordan


4

MATL, 9 bytes

2Y2"@X@Y"

Try it online!

Explanation

2Y2     % Push string 'abc...z'
"       % For char in that string each
  @     %   Push current char
  X@    %   Push iteration index (1-based)
  Y"    %   Run-length decoding: repeat char that many times
        % Implicit end. Implicit display

Do you know why & can't be used to duplicate and transpose 2Y2?
— Stewie Griffin

@StewieGriffin & doesn't actually duplicate and transpose, although it sometimes produces the same result as that. What it does is modify the number of inputs/outputs of the next function. For example, if you use &+, the + function now takes one input instead of two, and outputs the sum of the input with itself transposed. But that's only because that's how + work with 1 input (same for =, > and some others)
— Luis Mendo


4

Jelly,  5  4 bytes

sneaky Python implementation abuse

-1 byte thanks to Adám (outputting a list of lines has been allowed; as, now, has writing a function rather than a program)

Øa×J

A niladic link that returns a list of strings, the lines
(to print it with the newlines as a full program just add Y back in).

Try it online! (the footer calls the link as a nilad (¢) and gets the Python representation of the result (ŒṘ) for clarity as the default full-program behaviour would smash the result together like abbccc...)

How?

Øa×J - main link: no arguments
Øa   - yield the alphabet = ['a','b','c',...,'z']
   J - range of length    = [1,2,3,...,26]
  ×  - multiplication     = ["a","bb","ccc",...,"zzzzzzzzzzzzzzzzzzzzzzzzzz"]
     - (Python multiplication lengthens chars to strings - not usually a Jelly thing)

1
— Adám

hmm, maybe - we may "output" a list of lines, but we must "create a program" - when running as a program the output of the four byter is smashed to have no indication of it's list nature.
— Jonathan Allan

program or function
— Adám

4

MATL, 11 bytes

2Y2t!g*!YRc

Try it online!

Uses broadcast multiplication with ones to get a big square 26x26 matrix of the desired letters. Next, the lower triangular part is taken, and implicitly printed.

Also 11 bytes:

2Y2!t~!+YRc  % Using broadcast addition with zeroes
2Y2!l26X"YR  % Using 'repmat'

@StewieGriffin I was actually halfway commenting on your Octave answer on the coincidence of coming up with the same solution.
— Sanchises

4

Javascript, 87 bytes, 72 bytes (A lot of thank to @steenbergh)

My first answer too:

for(i=1,j=97;j<123;){console.log(String.fromCharCode(j++).repeat(i++))};

Welcome! Looks like you can shorten it a bit by removing the spaces around ind=1at the start, the semicolon after i<123 and the final semicolon. also, please make your header slightly more clear by stating language - bytecount, prefixed with a #.
— steenbergh

You can save six bytes by dropping j altogether: for(i=1;i<27;){console.log(String.fromCharCode(i+96).repeat(i++))}
— steenbergh

@steenbergh thank you once again, your how kind you are to help me.
— NTCG

4

Japt, 9 7 bytes

Outputs an array of lines

;C¬Ëp°E

Try it


Explanation

Split (¬) the lowercase alphabet (;C) to an array of characters, map over the array (Ë) and repeat (p) the current element by the current index (E) incremented (°) times.


Exactly what I had, except I used ®p°Y
— ETHproductions

3

Pip, 9 bytes

FczPcX++i

Try it online!

In pseudocode, this is

For-each c in z
    Print (c string-multiply ++i)

where z is preset to the lowercase alphabet and i is preset to 0.


Map-based solutions take one extra byte because they need the -n flag to display on multiple lines:

{aX++i}Mz
B X_+1MEz

3

Acc!!, 66 bytes

Count i while 26-i {
Count j while i+1-j {
Write 97+i
}
Write 10
}

Try it online!

With comments

# Loop i from 0 to 25
Count i while 26-i {
    # Loop j from 0 to i (inclusive)
    Count j while i+1-j {
        # Print a letter
        Write 97+i
    }
    # Print a newline
    Write 10
}


3

R, 38 bytes

A relatively uninteresting answer. Iterate for i from 1 to 26, print the ith letter of the alphabet i times (with an implicit line break).

for(i in 1:26)print(rep(letters[i],i))

Try it online!

A more interesting approach might be to use something like the following:

cat(letters[(1:351*2)^.5+.5])

This gives us all the letters in the right amount, but no linebreaks. Perhaps someone smarter than me can figure out a way to use that to make a golfier answer.


2
I'm not sure how to use your second approach, either, but I know that rep(letters, 1:26) is much shorter...
— Giuseppe

@Giuseppe Hah! Like I said, "someone smarter than me" is definitely needed.
— rturnbull




3

J, 18 17 bytes

a.{~(#"0+&96)i.27

Explanation:

              i.27      - list of integers 0 - 26
     (   +&96)          - adds 96 to the above list (starting offset of 'a')
      #"0               - copies the right argument left argument times  
  {~                    - select items from a list (arguments reversed)
a.                      - the whole alphabet


#"0 +&96 is a hook, which means that at first +96 is applied to the list i.27,
resulting in a list 96, 97, 98... 122, then #"0 is applied to this result. 
So it is evaluated as ((i.27)#"0(96+i.27)){a:

Try it online!



3

Octave, 25 24 bytes

['',tril((x=65:90)'+~x)]

Try it online!

Saved one byte thanks to Giuseppe who informed me that OP allows upper case letters.

Explanation:

Create a vector x with the ASCII-values of the upper case alphabet, and transpose it. Add the negated x (thus 26 zeros, in a row vector, in order to create a grid with (the ASCII-values of):

AAAA
BBBB
CCCC

Take the lower triangular matrix and convert to characters by concatenating with the empty string.


3

C (gcc), 48 bytes 50 bytes

Re-runnable version, as per cleblanc and Steadybox in the comments below.

s[9];main(i){for(;i<27;)puts(memset(s,i+95,i++));}

Try it online!


1
Nice answer. I think your function will fail the next time it's called and according to this link it should be re-useable; codegolf.meta.stackexchange.com/questions/4939/…
— cleblanc

Here's a fixed version in 50 bytes: s[9];main(i){for(;i<27;)puts(memset(s,i+95,i++));} Still beats my answer by a few bytes :)
— Steadybox


3

Japt, 17 16 11 bytes

-5 bytes thanks to Oliver

In ISO-8859-1

;26ÆCgX pXÄ

Not the best score, but I'm still a novice. Any suggestions are very welcome.

Outputs list of lines, as OP allowed. Link contains 3 bytes more for newlines.

Try it online!

;                      - Use string variables
 26                    - Literal 26
   Æ                   - For range 0..26
    C                  - Alphabet
     gX                -         . character at index X
        pXÄ            - Duplicate X+1 times
                       - End function (implicit)

1
Nice! 1oBÊÄ can be replaced by 26õ. You can save a couple more bytes by doing something like ;26ÆCgX pXÄ
— Oliver

@Oliver How the heck I didn't see that 26 is shorter than alphabet length?! Thanks. Also, my bad I didn't found that o takes the f argument...
— RedClover
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