রুবি ২.6+
রুবি'র পরিচয় difference
2.6 তে।
এটি এখানে একটি খুব দ্রুত, খুব পঠনযোগ্য সমাধান দেয়:
a = [1, 2, 3, 4, 5, 6]
b = [1, 2, 3, 4, 5, 6]
a.difference(b).any?
a.difference(b.reverse).any?
a = [1, 2, 3, 4, 5, 6]
b = [1, 2, 3]
a.difference(b).any?
মানদণ্ড চালানো:
a = Array.new(1000) { rand(100) }
b = Array.new(1000) { rand(100) }
Benchmark.ips do |x|
x.report('sort') { a.sort == b.sort }
x.report('sort!') { a.sort! == b.sort! }
x.report('to_set') { a.to_set == b.to_set }
x.report('minus') { ((a - b) + (b - a)).empty? }
x.report('difference') { a.difference(b).any? }
end
sort 13.908k (± 2.6%) i/s - 69.513k in 5.001443s
sort! 14.656k (± 3.0%) i/s - 73.736k in 5.035744s
to_set 5.125k (± 2.9%) i/s - 26.023k in 5.082083s
minus 16.398k (± 2.2%) i/s - 83.181k in 5.074938s
difference 27.839k (± 5.2%) i/s - 141.048k in 5.080706s
আশা করি যে কাউকে সাহায্য করবে!