এখানে পাইথন 3 স্ক্রিপ্ট রয়েছে যা ডিলিমিটরদের দ্বারা সরবরাহ করা ফাইলের নামের উপর ভিত্তি করে একাধিক ফাইলগুলিতে একটি ফাইলকে বিভক্ত করে। উদাহরণ ইনপুট ফাইল:
# Ignored
######## FILTER BEGIN foo.conf
This goes in foo.conf.
######## FILTER END
# Ignored
######## FILTER BEGIN bar.conf
This goes in bar.conf.
######## FILTER END
লিপিটি এখানে:
#!/usr/bin/env python3
import os
import argparse
# global settings
start_delimiter = '######## FILTER BEGIN'
end_delimiter = '######## FILTER END'
# parse command line arguments
parser = argparse.ArgumentParser()
parser.add_argument("-i", "--input-file", required=True, help="input filename")
parser.add_argument("-o", "--output-dir", required=True, help="output directory")
args = parser.parse_args()
# read the input file
with open(args.input_file, 'r') as input_file:
input_data = input_file.read()
# iterate through the input data by line
input_lines = input_data.splitlines()
while input_lines:
# discard lines until the next start delimiter
while input_lines and not input_lines[0].startswith(start_delimiter):
input_lines.pop(0)
# corner case: no delimiter found and no more lines left
if not input_lines:
break
# extract the output filename from the start delimiter
output_filename = input_lines.pop(0).replace(start_delimiter, "").strip()
output_path = os.path.join(args.output_dir, output_filename)
# open the output file
print("extracting file: {0}".format(output_path))
with open(output_path, 'w') as output_file:
# while we have lines left and they don't match the end delimiter
while input_lines and not input_lines[0].startswith(end_delimiter):
output_file.write("{0}\n".format(input_lines.pop(0)))
# remove end delimiter if present
if not input_lines:
input_lines.pop(0)
অবশেষে আপনি কীভাবে এটি চালাচ্ছেন তা এখানে:
$ python3 script.py -i input-file.txt -o ./output-folder/