আমি jQuery ব্যবহার করে একটি সাধারণ বৈধতা ফর্ম তৈরি করেছি। ঠিক আছে কাজ করছে। জিনিসটি আমি আমার কোড থেকে সন্তুষ্ট নই। একই কোড আউটপুট ফলাফল সহ আমার কোড লিখতে অন্য উপায় আছে?
$(document).ready(function(){
$('.submit').click(function(){
validateForm();
});
function validateForm(){
var nameReg = /^[A-Za-z]+$/;
var numberReg = /^[0-9]+$/;
var emailReg = /^([\w-\.]+@([\w-]+\.)+[\w-]{2,4})?$/;
var names = $('#nameInput').val();
var company = $('#companyInput').val();
var email = $('#emailInput').val();
var telephone = $('#telInput').val();
var message = $('#messageInput').val();
var inputVal = new Array(names, company, email, telephone, message);
var inputMessage = new Array("name", "company", "email address", "telephone number", "message");
$('.error').hide();
if(inputVal[0] == ""){
$('#nameLabel').after('<span class="error"> Please enter your ' + inputMessage[0] + '</span>');
}
else if(!nameReg.test(names)){
$('#nameLabel').after('<span class="error"> Letters only</span>');
}
if(inputVal[1] == ""){
$('#companyLabel').after('<span class="error"> Please enter your ' + inputMessage[1] + '</span>');
}
if(inputVal[2] == ""){
$('#emailLabel').after('<span class="error"> Please enter your ' + inputMessage[2] + '</span>');
}
else if(!emailReg.test(email)){
$('#emailLabel').after('<span class="error"> Please enter a valid email address</span>');
}
if(inputVal[3] == ""){
$('#telephoneLabel').after('<span class="error"> Please enter your ' + inputMessage[3] + '</span>');
}
else if(!numberReg.test(telephone)){
$('#telephoneLabel').after('<span class="error"> Numbers only</span>');
}
if(inputVal[4] == ""){
$('#messageLabel').after('<span class="error"> Please enter your ' + inputMessage[4] + '</span>');
}
}
});
$('form')[0].checkValidity()